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-3.8x^2+2.5x=0
a = -3.8; b = 2.5; c = 0;
Δ = b2-4ac
Δ = 2.52-4·(-3.8)·0
Δ = 6.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.5)-\sqrt{6.25}}{2*-3.8}=\frac{-2.5-\sqrt{6.25}}{-7.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.5)+\sqrt{6.25}}{2*-3.8}=\frac{-2.5+\sqrt{6.25}}{-7.6} $
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